Instead of just 3 pegs for the hoops to be on, try 4, or even higher. I haven't played with that yet, but my prediction is that it would take less steps, but the algorithm might be harder to produce. (Of course I may be wrong, I'll have to try this sometime to see if my prediction was right or wrong!)
It will either take less or equal. Because if it takes more moves then you could just ignore the last peg and then use the method you used without the last peg.
Instead of just 3 pegs for the hoops to be on, try 4, or even higher. I haven't played with that yet, but my prediction is that it would take less steps, but the algorithm might be harder to produce. (Of course I may be wrong, I'll have to try this sometime to see if my prediction was right or wrong!)
It will either take less or equal. Because if it takes more moves then you could just ignore the last peg and then use the method you used without the last peg.